A:($32+$45+$39)divided by3
B:3x $32+$45+$39
C:$32+$45+$39divided by 3
D:$32 divided by 3+$45divided by 3+$39
2006-12-05 23:51:37 · 16 answers · asked by Angel E 2 in Science & Mathematics ➔ Mathematics
option A
2006-12-05 23:54:42 · answer #1 · answered by raj 7 · 0⤊ 0⤋
You add the three prices together
32+45+39=116
Divide your answer by the number of books (3)
116/3=38.66666
2006-12-05 23:55:40 · answer #2 · answered by Tami C 3 · 0⤊ 0⤋
OPTION A
You add the three prices together
32+45+39=116
Divide your answer by the number of books (3)
116/3=38.70
2006-12-06 00:00:59 · answer #3 · answered by praveen_silicon 2 · 0⤊ 0⤋
Will Bought 3 College Textbooks
2017-01-09 09:23:52 · answer #4 · answered by ? 4 · 0⤊ 0⤋
$32+$45+$39=$116/3=38.666666
2006-12-06 00:01:45 · answer #5 · answered by Anonymous · 0⤊ 0⤋
You add the three prices together
32$+45$+39$=116$
Divide your answer by the number of books i.e. 3
116$/3=38.67$
so you're average cost of each book is 38.67$
so correct option is 'A'
2006-12-06 00:30:57 · answer #6 · answered by rupin27 2 · 0⤊ 0⤋
A) = 39 bux
2006-12-05 23:59:10 · answer #7 · answered by unan1m0us 5 · 0⤊ 0⤋
Answer is option A
2006-12-06 00:03:39 · answer #8 · answered by ATS 2 · 0⤊ 0⤋
A.
Average of n numbers is = sum of numbers/ n
2006-12-05 23:56:58 · answer #9 · answered by anami 3 · 0⤊ 0⤋
Averaging is always solved with option A,, :-)=
2006-12-06 00:01:02 · answer #10 · answered by Jcontrols 6 · 0⤊ 0⤋