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How much work is done by the motor in a CD player to make a CD spin, starting from rest? The CD has a diameter of 12.7 cm and a mass of 14.8 g. The laser scans at a constant tangential velocity of 1.22 m/s. Assume that the music is first detected at a radius of 19.5 mm from the center of the disk. Ignore the small circular hole at the CD's center?

The answer that the book has is 0.0584 J
How do "they" come up with that crazy number??

2006-12-05 19:11:26 · 4 answers · asked by Moose 2 in Science & Mathematics Physics

4 answers

The energy of the disc spinning is .5*I*w^2. I=.5*M*Rd^2 (Rd = 12.7/2 cm). Angular velocity w = tangential velocity/Rl (Rl is 19.5mm). Just do the calcs, but be careful to keep the units straight (you have meters, cm and mm) The book has the right answer.

2006-12-05 19:43:27 · answer #1 · answered by gp4rts 7 · 0 0

The work done is to add an angular momentum (via a torque) to accelerate the disk from rest to the specified speed. The trick is that the moment of inertia of a disk is equivalent to a mass situated at a distance part way between the center and the edge. The exact location can be determined by calculus, or by looking it up in a table. Checking my favorite table, the moment of inertia is mr*2/2. With that bit of wisdom, you should be able to work it out.

2006-12-05 19:23:22 · answer #2 · answered by Anonymous · 0 0

Radius of cd, R=6.35 cm = 6.35E-2 m
Mass M= 14.8 g = 14.8E-3 kg
Momemt of Inertia, I= 0.5* M*R^2
Angular velocity, w= 1.22/19.5E-3 radians/s
You are looking for the work done, which will be the kinetic energy given to the cd
=0.5* I*w^2= 0.06J
Simple isn't it!

BTW, the notation E refers to 10 power, * is multiplication and ^ is for exponent, in case you dont know.

2006-12-05 19:48:38 · answer #3 · answered by Defunct 2 · 1 0

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2016-12-11 03:10:16 · answer #4 · answered by Anonymous · 0 0

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