The largest mincemeat pie ever created had a mass of 1020 kg. suppose the pie of this mass slides down a ramp that is 18 m long and is inclined to the ground be 10 degrees. if the coefficient of kinetic friction is 0.13, what is the net work done on the pie during it's decent?
2006-12-05 16:11:12 · 3 answers · asked by maggie 1 in Science & Mathematics ➔ Physics
If the ramp is inclined at a 10° angle the normal force against the ramp is
1020*9.8*cos(10) = 9853.8 N. The coefficient of kinetic friction is .13 so the frictional force is
9853.8*.13 = 1281 N and 1281 N through a distance of 18 meters is
1281*18 = 23058 J.
Doug
2006-12-05 16:21:43 · answer #1 · answered by doug_donaghue 7 · 1⤊ 0⤋
Kilograms are mass. Newtons are force. If you mean converting mass to weight in the earths gravitational field, multiply mass in kg by 9.8 to get weight in N.
2006-12-06 00:13:46 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
(m)
To convert kilograms to newtons multiply it into 9.807
2006-12-06 00:17:30 · answer #3 · answered by mallimalar_2000 7 · 2⤊ 0⤋