calculate the horizontal force that must be applied to produce an acceleration of 1.8 g for a 1.2-kg puck on a horizontal friction-free air table.
2006-12-05 11:12:20 · 6 answers · asked by smile 3 in Science & Mathematics ➔ Physics
I'm not sure of the units you have used - do you mean 1.8 x gravity (g)? If so the acceleration due to gravity is 9.81 m/s/s, so 1.8 x this is 17.658 m/s/s.
Using F = ma
Force = 1.2 x 17.658 = 21.19 N (don't forget your units, it gets you extra marks).
Hope this helps - physics can get a bit boring!!
2006-12-05 12:09:58 · answer #1 · answered by Billy 2 · 0⤊ 0⤋
F=ma
F=1.2(1.8x9.81)
F=21.1896 N
2006-12-06 13:51:24 · answer #2 · answered by Kemmy 6 · 0⤊ 0⤋
Assuming 2.0 g is two.0 gravity then: F=ma, a= 19.62ms^-2 [or 20^-2 in case you're taking g to be 10], m = a million.2 a million.2*19.sixty two=23.54400N a million.2*20.00=24N Please do your guy or woman H'paintings in destiny :D
2016-10-14 02:35:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Depends what value to take g as (I used 9.7801) to give a value of 21.125016N
F=ma
a=g*1.8
m=1.2
so
F=1.2*1.8*g
2006-12-05 20:51:11 · answer #4 · answered by Mark G 7 · 0⤊ 0⤋
I'd go with Newton's second law F = ma, but that's just me.
2006-12-05 11:16:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I reckon 21.6 Newtons.
2006-12-05 11:15:41 · answer #6 · answered by jimbo_thedude 4 · 0⤊ 0⤋