2006-12-05 10:12:29 · 8 answers · asked by jude46m 1 in Education & Reference ➔ Words & Wordplay
based on the PH table which ranges from 1-14 determining if something is more acidic or alkaline.
1 is acidic
7 is nuetral
14 is alkaline
so ph10 is in between nuetral - alkaline
2006-12-05 10:17:19 · answer #1 · answered by Anonymous · 0⤊ 0⤋
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It all means nowt to me - but at least we're not talking about acid levels anymore!
...what's a "renishaw"?
(quick search)
Something to do with metrology.
...what's metrology?
(quick search)
...wikipedia link pasted... but I've kinda lost the will to live now!
2006-12-05 18:43:26 · answer #2 · answered by franja 6 · 1⤊ 0⤋
PH10 means the solution is alkaline. 7 is neutral 0 is highest acid and 14 highest alkaline. the scale is the measure of the concentration of the hydrogen/ion in the solution
2006-12-05 18:19:14 · answer #3 · answered by Maid Angela 7 · 0⤊ 0⤋
Should always be written as pH. The technical explanation is that pH is the negative logarithm of the Hydrogen ion concentration.
At ambient conditions, water has a pH of 7.0. That's neutral - not acidic, not basic.
As you add something basic to the water - ammonia, drain cleaner, lye, etc. - the pH increases up to a maximum of 14. That is a strong base and is dangerous. Anything above a pH of 12 should be avoided or only handled with protective equipment - face shield, proper gloves, etc.
A pH of 10 is a moderate base.
2006-12-05 18:29:27 · answer #4 · answered by dollhaus 7 · 0⤊ 0⤋
Something with a pH of 10 is an Alkaline (like calcium) pH 7 is neutral and anything below that is an acid.
Hope this helps.
2006-12-05 18:25:29 · answer #5 · answered by Jenni 4 · 0⤊ 0⤋
You got it KP,
I work in the chemical industry
2006-12-05 18:20:39 · answer #6 · answered by DEQSAN 2 · 0⤊ 0⤋
means that the solution is on the alkali peak
2006-12-05 18:15:34 · answer #7 · answered by Splishy 7 · 0⤊ 0⤋
lol its either very accidic or very alchaline!! 95% sure its accidic coz PH 7 is nutrel
2006-12-05 18:15:34 · answer #8 · answered by Cap10kirk 3 · 0⤊ 2⤋