2006-12-05 10:06:45 · 10 answers · asked by p3mk13 1 in Society & Culture ➔ Cultures & Groups ➔ Lesbian, Gay, Bisexual, and Transgender
San Francisco, followed by Seattle, Atlanta, Minneapolis, and Boston.
(It should also be noted the numbers are based on same-sex coupled households and does not include the number of single gay people, which is not measured by the census.)
2006-12-05 10:15:15 · answer #1 · answered by χριστοφορος ▽ 7 · 0⤊ 0⤋
San Francisco
2006-12-05 18:57:52 · answer #2 · answered by ttjakt 6 · 0⤊ 0⤋
The City of Wilton Manors Florida, Also Fort Lauderdale AKA Fort LaTi Da
2006-12-05 20:08:16 · answer #3 · answered by mattahew 2 · 0⤊ 0⤋
San Francisco - The Castro District
2006-12-05 18:44:02 · answer #4 · answered by ~Twisted Sister~ 4 · 0⤊ 0⤋
People above have listed a lot of cities with a high population of gay households, or a large active gay community. That's cool.
But, a few years ago "Out" magazine ranked Columbus, Ohio as the most livable city in America for gay and lesbian people. This was based on civil rights laws, gay community, cost of living and a lot of other factors.
2006-12-05 21:35:13 · answer #5 · answered by ? 6 · 0⤊ 0⤋
San Fransisco
2006-12-05 18:35:24 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Washington DC ranks right up there with the best of them.
Atlanta, LA, New York, Chicago...any really large city is going to be a Gay attraction. Key West is not very gay any longer. MIami/South Beach is as Gay a place as any I have been. San Diego has a very large Gay population, San Francisco is not as gay as you would think, but has a sizable gay population.
2006-12-05 18:14:43 · answer #7 · answered by Anonymous · 0⤊ 0⤋
The city with the most gays is Los Angeles or San Fransisco. Can't remember which.
2006-12-05 18:10:55 · answer #8 · answered by guitarfreakajg 2 · 0⤊ 1⤋
I'm guessing Key West?
2006-12-05 18:10:41 · answer #9 · answered by mattmedfet 3 · 0⤊ 0⤋
i think
SAN FRANCISCO
I TOTALLY LOVE SAN FRANCISCO IS REALLY KOOL!!!
2006-12-05 19:09:11 · answer #10 · answered by Anonymous · 0⤊ 0⤋