What weights of Bovine Serum Albumin (molecular weight 66,000) are required to give solutions of 10ml and 100ml volumes containing 1μmole of BSA?
2006-12-05 09:33:57 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
1) 1 mole of BSA is equal to 66,000 grams, so 1µmole is equal to 66,000/1000,000 = 0.066 grams
2) Mass of BSA present in 10 mL of solution 1µM is:
gr of BSA = (0.0066g)(10 mL)/1000mL= 0.000066 grams
3) Mass of BSA present in 100 mL of solution is:
gr of BSA = (0.0066g)(100mL)/1000mL = 0.00066 grams
That's it!
Good luck!
2006-12-05 09:54:14 · answer #1 · answered by CHESSLARUS 7 · 0⤊ 0⤋
Albumin Molecular Weight
2016-11-01 12:32:28 · answer #2 · answered by dopico 4 · 0⤊ 0⤋
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What weights of Bovine Serum Albumin (molecular weight 66,000) are required to give solutions of 10ml and 100m
What weights of Bovine Serum Albumin (molecular weight 66,000) are required to give solutions of 10ml and 100ml volumes containing 1μmole of BSA?
2015-02-03 04:15:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
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2015-02-08 04:52:08 · answer #4 · answered by Anonymous · 0⤊ 0⤋