You have a 2.5mM solution of alanine (molecular weight 89.1). If you dilute this solution 1:10 to yield 10mls?

Question

You have a 2.5mM solution of alanine (molecular weight 89.1). If you dilute this solution 1:10 to yield 10mls of the new solution how much alanine does it contain?

Answer 1

1) One liter of solution 2.5 mM of alanine contains 0.0025 moles of alanine which is equivalent to (0.0025 molesX 89.1 g/mole) = 0.2227 grams.

2) Hence if one liter contains 0.2227 grams of alanine, 10 mL contains (0.2227 g)(10 mL)/1000mL = 0.0002227 grams

That's it!

Good luck!

Answer 2

a million umole is a weight, no longer a concentration- Its like asking what weight is critical to make 5 kilos. A mole of BSA is 66000 g, subsequently a millionth of that (umole) is 0.066 g, or sixty six mg. So, sixty six mg is a million umole of BSA. Now, shall we assume you meant to assert a million uMolar, that's a concentration-i.e. moles consistent with liter sixty six mg BSA in a million liter is a million umole. So is you have a million/10 the quantity, you p.c. a million/10 the BSA. So, for a 100ml volume, you p.c. 6.6 mg, and for 10 ml, you p.c. 0.sixty six mg.