One More, What am I doing wrong in this algebra problem. (Logs)?

Question

3^x/2 = 15

I started with log (3^x / 2) = log15
then went xlog9 = log15
finished with x=log15 / log9

I think it was when I took the x out, I kept the 2 and took 3 to the 2 and got 9. What should I do?

Answer 1

log (3^x / 2) = log15
(x / 2)log9 = 2log15
xlog9 = 2log15
x = ((2log15) / (log9))