A radioactive nucleus at rest decays into a second nucleus, an electron, and a neutrino. The electron and neutrino are emitted at right angles and have momenta of 9,30x10^-23 kg.m/s and 5,4x10^-23 kg.m/s respectively.
What are the magnitude and direction of the momentum of the second ( recoiling) nucleus?
2006-12-05 06:40:07 · 4 answers · asked by nice_ girl 1 in Science & Mathematics ➔ Physics
Momentum is conserved in this decay (which is why the neutrino is necessary). Without loss of generality, assume the electron is emitted down and to the left at an angle of 45 degrees to the horizontal. Then the neutrino is emitted down and to the right at an angle of 45 degrees to the horizontal, as required by the right angle between their paths. The nucleus, to conserve momentum must recoil upward, making an angle of 90 + 45 degrees = 135 degrees with respect to either the electron or the neutrino path. The horizontal momentum is zero. The vertical momentum is the sum of the vertical components of the electron and neutrino momentum, which is SQRT 2 x (9.3 + 5.4) x 10^(-23) = 10.39 x 10^(-23) kg.m/sec.
2006-12-05 07:17:30 · answer #1 · answered by hevans1944 5 · 0⤊ 0⤋
Find the resultant vector by using the law of parallelogram i.e.
Resultant=(A^2+B^2+2ABcos theta)^1/2
Put the values and you will get the resultant.
The magnitude of momentum of recoil of nucleus will be same as that of resultant . Find the direction of resultant ,by using formula (b*sin theta )/(a+b*cos theta),the direction of recoil will be opposite to the direction of resultant.
That's it!!!!
2006-12-05 07:21:03 · answer #2 · answered by Steel 2 · 0⤊ 0⤋
hi Ben R, given 20 m because the height of the progression. You height is a million.7m So (20-a million.7) m is seen from a distance say x m. So tan 30 = (20-a million.7) / x Or x = 18.3 / tan 30 fixing we get x, ie the gap from the progression = 31.7 m
2016-11-23 18:28:01 · answer #3 · answered by ? 4 · 0⤊ 0⤋
There are many interpretations of quantum physics.
American physicist J.A.Wheeler had a hobby:
He collected different interpretations of quantum physics.
Here is one more interpretation of the quantum theory.
www.socratus.com
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2006-12-05 07:14:11 · answer #4 · answered by socratus 2 · 0⤊ 1⤋