Simplify each expression?

Question

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Question D... I'm lost. HELP!!!!!!!!

Answer 1

PEMDAS
rules of precedence called "order of operations", the "operations" being addition, subtraction, multiplication, division, exponentiation, and grouping.

A common technique for remembering the order of operations is the abbreviation "PEMDAS", which is turned into the phrase "Please Excuse My Dear Aunt Sally" (or, as my husband prefers, "Purple Elephants May Destroy A School"). It stands for "Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction". This tells you the ranks of the operations: Parentheses outrank exponents, which outrank multiplication and division (but multiplication and division are at the same rank), and these two outrank addition and subtraction (which are together on the bottom rank). When you have a bunch of operations of the same rank, you just operate from left to right.

8^0 = 1 (anything to the 0 power = 1 by definition)
square root(121) = 11
11 + 1 = 12
square root(25/144) = square root(25) / square root(144) = 5/12
5/12 * 12 = 5
5 + 3^2 = 14

Answer 2

The problem with questions like D is that a square root usually has two answers, + and -. The square roots of 25 are 5 and -5.

So, you can have up to four answers for D.

And I also question B. Does it start with (-6)² or -(6²). I'm left to assume that it is the latter, because the order of precidence is that the exponent is raised before the sign is applied. So the first factor in this would be -36.

Answer 3

5(2^2 + 4^3)

2^2 = 2*2 = 4
4^3 = 4*4*4 = 64

5(4 + 64) = 5(68) = 340


-6^2(3^2 - 7^0)

x^m/x^n = x^(m - n)
7^2/7^2 = 7^(2 - 2) = 7^0 = 1

-36(9 - 1) = -36(8) = -288


((30 - 3(2)^2)/2)^(1/2)

x^(1/2) = sqrt(x)
Work from innermost parentheses

sqrt((30 - 3(4)/2)
sqrt((30 - 12)/2)
sqrt(18/2)
sqrt(9)
3


sqrt(25/144)(8^0 + sqrt(121) + 3^2)
(5/12)(1 + 11 + 9)
5*21/12
5*7/4
35/4

Answer 4

5/12 * (1+11) + (9)


5/12 * 12 + 9

5+ 9

=

14

Answer 5

the final rule you virtually continuously opt for to adhere to is grouping like words For a million you opt for to team each and each and every of the s words and the numbers a million) 6s+5-(s-6) first simplify with techniques from eliminating the () and replacing the sign up all words by way of adverse so: 6s+5-s+6 then team 6s-s=5s and +5+6=11 so 5s+11 for 2 follow same steps yet you've x's, y's and numbers 2)2x+y-(9-4x) same step on () 2x+y-9+4x then team 2x+4x=6x ; the y and -9 are lone words so 6x+y-9

Answer 6

(5/12)(1+11)+9
=(5/12)(12)+9
=5+9
=14