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I have to find the length of the diagonal of a rectangle...the length is 6 meters and the width is 4 meters. I have to give an exact answer and give an approximate answer

2006-12-05 03:54:02 · 13 answers · asked by aj_izmixedlyk3gumbo 4 in Science & Mathematics Mathematics

13 answers

c=rt(a^2+b^2)
=rt(36+16)
=2rt13 sq.m

2006-12-05 04:11:00 · answer #1 · answered by raj 7 · 0 0

In any right triangle, the area of the square whose side is the hypotenuse (the side of a right triangle opposite the right angle) is equal to the sum of areas of the squares whose sides are the two legs (i.e. the two sides other than the hypotenuse).
If we let c be the length of the hypotenuse and a and b be the lengths of the other two sides, the theorem can be expressed as the equation

c^2 = a^ 2 + b^2


This equation provides a simple relation among the three sides of a right triangle so that if the lengths of any two sides are known, the length of the third side can be found.

c^2 = 6^2 + 4^2

c^2 = 36 + 16

c^2 = 52

c = sqrt( 52)

c = 7.211 meters

2006-12-05 05:04:51 · answer #2 · answered by Fizz 2 · 0 0

use the pathagorean theorum a^2 + b^2 = c^2

let a = 6 and b = 4

6^2 = 36 an 4^2 = 16

36 +16 = 52

find the square root of 52 and you have your answer. This works wih all right triangles.

2006-12-05 04:07:19 · answer #3 · answered by ikeman32 6 · 0 0

All working out as Pythagorus, already mentioned.

Result is square root of 52

Approxiamate answer - estimate what 2 numbers multiplied together give 52

7 x 7 = 49 and 8 x 8 = 64

so it's between 7 and 8 , but closer to 7 (49 closer to 52)

Calculator for exact answer gives 7.211...

Ask your teacher if you don't understand

2006-12-05 05:48:30 · answer #4 · answered by jonny red 4 · 0 0

Using Pythagoras Theorem,

d^2 = 6^2 + 4^2
d^2 = 36 + 16
d^2 = 52
d = SQRT 52
d = approximately 7 (as SQRT 49 is 7)
and exactly 7.21 (to 3 significant figures)

2006-12-05 04:56:28 · answer #5 · answered by Kemmy 6 · 0 0

a squared + b squared = c squared
or
6 x 6 + 4 x 4 = c x c
or
36 + 16 = square root of 52
or
7.2111025 meters

2006-12-05 04:00:53 · answer #6 · answered by Anonymous · 0 0

d^2 = 6^2 +4^2 = 36+16 = 52

d = (52)^0.5 = 7.21

2006-12-05 03:59:05 · answer #7 · answered by maussy 7 · 0 0

use pythag

4^2 + 6^2 = Diagonal^2

so 16+36 = diagonal^2

52=diagonal^2
sqrt(52)=diagonal

if you cant follow this, you must try to do your homework on your own!!

2006-12-05 03:56:40 · answer #8 · answered by Anonymous · 1 0

a^2 = b^2 + c^2

a^2 = (6*6)+(4*4)

= 36 + 16

= 52

a = sq. root of 52
(cant work it out cos i dont have calculator)

2006-12-05 03:59:12 · answer #9 · answered by england til i die 3 · 0 0

Pythagorus my boy. The square on the hypotenuse is equal to the sum of the square of the other 2 sides (which are 6m and 4m)

2006-12-05 03:56:20 · answer #10 · answered by leedsmikey 6 · 2 0

We know that
Area of rect. = l*b
Also,
Area = 1/2 *diagonal^2

So
Area = 6*4=24m^2

Also
24=1/2 * d^2

or 2=under root 48

=6.92820m

2006-12-05 04:01:58 · answer #11 · answered by shubhopriyo 2 · 0 2

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