How do you rearrange math equations?

Question

2x+3y-6=0

Answer 1

adding -2x+6
3y=-2x+6
dividing by 3
y=(-2/3)x+(6/3)
=(-2/3)x+2
if you want to make y the subject
however ifyou want to make 'x' the subject
adding -3y+6
2x=-3y+6
dividing by 2
x=(-3/2)y+(6/2)
=(-3/2)y+3

Answer 2

I'll guess this equation refers to a straight line and the answer you need is having it rearranged to the usual form for one. Since that form is always: y = ax + b, we have to move every term (part) without "y" in it to the right side so we subtract "2x" and "-6" from both sides: 2x - 2x + 3y - 6 - (-6) = 0 - 2x - (-6). The 2x - 2x is zero and -6 - (-6) (or - 6 + 6, if you like) is also zero so we get: 0 + 3y + 0 = -2x + 6 or: 3y = -2x + 6. Last step is to divide both sides by 3 to get just 1y on the left side: 3y/3 = -2x/3 + 6/3 or: y = –2/3 x + 2 (in case that makes it hard to read without characters for fractions, it is –2x divided by 3 (–2/3 x = –.667x); it is NOT –2 divided by 3x!)

Answer 3

Add 6 to both sides

2x + 3y -6 +6 = 0+6
2x +3y =6

2x+3y - 3y = 6 - 3y
2x = 6 - 3y

The important thing is that the equality sign means that both sides are equal - what you do to one side you must do to the other.

Answer 4

2x plus 3y -6=o
2x plus 3y=6
just change the place of the 6 on the right hand side and you must change the sign// (its so simple man are you in 5th class or what??/

Answer 5

y = -2/3 x +2= 2 (x/3 -1)

Answer 6

2x + 3y = 6
3y = 6 - 2x
y = 2 - (2x)/3