2006-12-05 02:27:32 · 3 answers · asked by hopper5191987 1 in Science & Mathematics ➔ Mathematics
you must have used a computer to ask this question, so use the computer to solve the equation! you dont have to be a rocket scientist to figure that out!
2006-12-05 02:35:27 · answer #1 · answered by Anonymous · 0⤊ 1⤋
ln (x^2 + 6x) = ln (x^2 + 6)
ln (x^2 + 6x) - ln (x^2 + 6) = 0
ln[(x^2 + 6x)/(x^2 + 6 )] = 0 [log m - log n = log (m/n)]
(x^2 + 6x ) / (x^2 + 6 )] = 10^0 ( if ln x = m then x = 10^ m)
x^2 + 6x = x^2 + 6 ( n^0 = 1)
6x = 6
x = 1
2006-12-05 02:38:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
take exponentials of both sides since both the logarithm and exponential are one-one functions for real x.
then
x^2 + 6x = x^2 + 6
6x = 6
x=1
2006-12-05 02:48:52 · answer #3 · answered by yasiru89 6 · 1⤊ 0⤋