In an enclosure filled with animals. There are 30 ft. and 9 heads in an enclosure of pigs and chickens.
2006-12-05 00:00:35 · 5 answers · asked by daineyjinh 1 in Science & Mathematics ➔ Mathematics
My guess would be six pigs and three chickens, but why are they all in one pen?
2006-12-05 00:11:34 · answer #1 · answered by Chrispy 7 · 0⤊ 0⤋
Let:
x = be the number of chickens
y = be the number of pigs
1st equation: x + y = 9
2nd equation: 2x + 4y = 30
From 1st, we get:
x = 9 - y
Substitute x in 2nd:
2(9-y) + 4y = 30
18 - 2y + 4y = 30
2y = 30 - 18
2y = 12
y = 6 and x = 3
So there are 6 pigs and 3 chickens
2006-12-05 08:13:08 · answer #2 · answered by euclidjr 2 · 1⤊ 0⤋
Let there be x pigs and y chickens
=>x+y=9...............each has 1 head
also 4x + 2y=30....pigs have 4 feet and chickens have 2
Therefore, x+y=9.............(i)
2x+y=15..........(ii)
subtract (i) from (ii)
=>x=6
and y=3
Therefore 6 pigs and 3 chickens
2006-12-05 08:21:22 · answer #3 · answered by sushant 3 · 1⤊ 0⤋
Who cares? Kill them all and have a barbecue
2006-12-05 08:02:35 · answer #4 · answered by silvs 5 · 0⤊ 3⤋
its impossible to know.
2006-12-05 08:10:42 · answer #5 · answered by gorjis gal 2 · 0⤊ 1⤋