13 + 13 - 6/3 = 24
6 * (13/13 + 3) = 24
(3+13/13)! = 24
(6 - 3 + 13/13)! = 24
(13 - 6 - 3)! = 24
you didnt say use them all.
these are all different.
2006-12-04 19:54:36
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answer #1
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answered by oscarD 3
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(13+13) - (6/3) = 24
6 * (3 + 13/13) = 24
13 - (6/3) + 13 = 24
(3 + 13/13) * 6 = 24
(-6/3) + 13 + 13 = 24
Edit: The last three equations are really just rearrangements of the first two equations.
If you can use factorial (!) then you have some more possibilities:
(3 + (13 - 13)!) * 6 = 24
6 * (3 + (13/13)!) = 24
(6 - 3 + (13/13))! = 24
((6 * (13 - 13))! + 3)! = 24
I like the last one because it uses all the four numbers but still manages to make 4! in a creative way.
2006-12-04 19:12:18
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answer #2
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answered by Puzzling 7
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Here are 5 different ways using ALL the numbers:
1) (3 + 13/13)*6
2) 13 + 13 - 6/3
3) (3 + (13 - 13)!)*6
4) (6 - 3 + 13/13)!
5) [3 + {arcos(13/13)}!]*6
2006-12-04 21:03:07
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answer #3
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answered by Wal C 6
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In Puzzling's answers, #1, #3, and #5 are the same; #2 and #4 are the same . So that is only TWO different equations.
VOTE FOR "OSCAR S"
2006-12-04 19:34:38
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answer #4
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answered by Overrated 5
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13 + 13 - 6 / 3
there's an obvious one
2006-12-04 19:13:04
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answer #5
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answered by Anonymous
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Puzzling got 'em all. Good job. Fun question.
2006-12-04 19:26:14
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answer #6
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answered by Gwen K 2
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(13+13)-(6/3)=24
-(6/3)+(13+13)=24
-6/3+13+13=24
13+(-6/3)+13=24
6/-3+13+13=24
2006-12-04 20:15:34
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answer #7
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answered by dnsnowden 2
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