Gravitational Force question?

Question

The star has a mass 3.35×10^5 times that of the planet, which orbits this star. For a person on the planet, the average distance to the center of the star is 2.39×10^4 times the distance to the center of the planet.

In magnitude, what is the ratio of the star's gravitational force on you to the planet's gravitational force on you?

Answer 1

your mass =m1
planet=m2
star = M

F1/F2=
G M*m1/R*R
-----------------
G m2*m1/r*r

=M*r*r/m2*R*R

but R/r=2.39*10^4
M/m2=3.35*10^5

F1/F2= 3.35*10^5/(2.39*10^4)^2
=0.5865*10^-3
=5.865*10^-4

ANS: Ratio of force of sun to that of planet is 5.865 * 10 ^ (-4)

Answer 2

Gravity isn't a force. It's an acceleration. (Don't they teach *any* thing in Physics classes anymore?) It only acts as a force when it interacts with mass (f = ma).

Call the product of the persons mass and the planets gravitational attraction g. Since the star has a mass of 3.35*10^5 times that of the planet, and is 2.39*10^4 times as far away (in terms of the center of mass) the force 'felt' by the individual would be
3.35*10^5/(2.39*10^4)² or about 5.86*10^-4 as much as the planets (gravitational acceleration falls off as 1/r²)


Doug

Answer 3

Ratio=
=(3.35*10^5)/(2.39*10^4)^2
=(3.35*10^5)/(5.71*10^8)
=3.35/5710
=0.00058

Therefore the planets gravitational force is greater.

Answer 4

The ratio is equal to the ratio of the masses divided by the square of the ratio of the distances. I get 5.86E-4. The ratios look suspiciously like the earth/sun system.

Answer 5

The 4 elementary forces of nature are: Electromagnetic stress, Gravitational stress, good nuclear stress and susceptible nuclear stress. All different forces derive from those 4. The maximum powerful is the coolest nuclear stress, observed with techniques from the Electromagnetic stress, observed with techniques from the susceptible nuclear stress and intensely last yet not least the Gravitational stress.

Answer 6

not that good at math 5=5 +12