If you fired 2 bullets. One at a 45 , and one straight up at a 90 , Which one will hit the ground first.?

Question

No variables, just 2 guns fired at the same rate at different angles.

Answer 1

The angle at which the guns fire the projectile (bullet) will effect the distribution of the overall projectile's speed into its X (horizontal) and Y (vertical) components.
Since perpendicular vectors (in this case, velocity vectors) are independent...the horizontal component of the bullet's velocity is irrelevant in determining how long each projectile stays in the air before hitting the ground, only the vertical component.

At 90 degrees, straight up in the air, the all of the bullet's speed will be in the vertical direction.
At 45 degrees, part of the bullet's speed will be in the horizontal direction, and part will be in the vertical direction (in this particular case, both components will have magnitudes equal to sqrt(2)/2 * the over all speed). The bullet fired at 45 degrees only has a horizontal velocity component at the expense of its vertical component (it had to give up some of its 'upward' speed to move 'sideways'), thus, it will have a smaller vertical component of its velocity.

The bullet with the larger vertical component of its velocity will stay in the air longer (assuming a level terrain). The bullet fired at 45 degrees will hit the ground first.

Answer 2

It depends on your starting velocity. If the both have the same starting velocity than the one at 45 because less of it's velocity is in the y direction (the velocity is split up between x and y, x=vcos45 and y=vsin45), if however they both are launched with equal y velocity (even though one has x velocity and the other doesn't), they'll hit the ground at the same time but in different spots. If the y velocity for the bullet fired at 45 is greater than that of the bullet fired at 90, the 90 degree bullet will land first.

assuming they are fired from the same gun on the same settings, they probably have the same total stating velocity, and the one at the 45 degree angle will land first.

note: by y velocity i mean velocity up and by x velocity i mean velocity out. why i say x=vcos/sin45, v is the starting velocity before it gets split up)

i hope that makes sense :-)

Answer 3

obviously the one fired at the 45 degree angle would hit the ground first. Because the one fired at 90 would have to fall from a higher distance than the one fired at a 45.

It would be like dropping a ball from 1000 feet versus dropping a ball from 100 feet.

Answer 4

The one fired at the 45° angle.


Doug

Edit: Amandeep, you need to think more about the vertical component(s) of velocity at the time the gun(s) are fired ☺

Answer 5

pay the bill,she were given off less costly,my mon exceeded out at the same time as in Galveston Island.Later their EMS despatched her a $2,000 bill for a 2 mile experience. Our community EMS has a voluntary fee of $5.00 in line with month further to the application bill,if the EMS is ever needed you pay no longer something.

Answer 6

for first t=2usintheta/g
for second t=2u/g
since sintheta<1 for angle not equal to 90
therefore the one at 45 degrees reach first

Answer 7

obviously 45, have u seen an arrow that goes forward and straight down?!

Answer 8

both will fall at same time. horizontal & vertical components of velocity act independent of each other.