If a pattern goes like this (1=1, 2=2, 3=4, 4=8, 5=15, 6=32, 7=64, 8=128, 9=256, 10=512) then what would be the equation using n as the variable for the first number and r for the second? I have trie this over and over again, but I can't find the answer. I would really appreciate it if you could help with this. Thanks
2006-12-04 15:30:54 · 6 answers · asked by ♥ 4 in Education & Reference ➔ Homework Help
Yes I did check the back of the book...twice.
2006-12-04 15:37:17 · update #1
Typo: Yes 5=16 not 15, sorry. Thanks for catching that.
2006-12-04 15:38:11 · update #2
are you sure that 5= 15 and not 16?
if 16, then it is r =2^(n-1)
for example 2 ^(1-1) = 2^0 which is 1
2^(2-1) = 2^1 which is 2
2^(3-1) = 2^2 which is 4, etc...
2006-12-04 15:36:18 · answer #1 · answered by Dako 2 · 1⤊ 0⤋
The equation is n+1=rx2.
The first #'s are increasing by 1 and the second #'s are doubling.
2006-12-04 15:43:33 · answer #2 · answered by LULU1218 2 · 0⤊ 0⤋
TRY THIS SITE IT SHOULD HELP YOU.
http://www.cs.trinity.edu/About/The_Courses/cs301/math-for-the-layman/
2006-12-04 15:35:43 · answer #3 · answered by debbie k 2 · 0⤊ 0⤋
it is
r=2^(n-1)
example
n=4
r=2^(4-1)=8
n=5
r=2^(5-1)
r=2*2*2*2=16
2006-12-04 15:46:28 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
did u check the back of the book?!
2006-12-04 15:32:40 · answer #5 · answered by hottie32566 1 · 0⤊ 1⤋
ask an azn
2006-12-04 15:32:44 · answer #6 · answered by Anonymous · 0⤊ 1⤋