help me please!?

Question

In your pocket you have a felt bag with some marbles. You have four(4) pearlies, two(2) starburst, and three (3) solid shooters. With this information you will answer the following questions.

Write the fractional chance of pulling out randomly, one of each on a first try when the bag is full?

What is the fractional chance of randomly not pulling out starburst on blind first try?

What is the fractional chance of randomly not pulling out a shooter on blind first try?

Answer 1

#1 pearlies - 4/9; starburst 2/9; shooters 1/3
I was a bit confused by this question - these are the fractions for picking a pearly first if the bag is full, the fraction for picking a starburst first if the bag is full, and the fraction for picking a shooter if the bag is full. I hope that's what you were looking for.
#2 7/9
#3 2/3

Answer 2

There are nine marbles in total.

The fractional chance of pulling out one of each type of marble is, respectively:

4/9 for the pearlie
2/9 for the starburst
and
3/9 or 1/3 for the solid shooters.

The fractional chance of randomly not pulling out a starburst would be equal to the sum of the probabilities of choosing either a perlie or a solid shooter.

4/9 + 3/9 = 7/9

There is a 7/9 chance of randomly NOT pulling out a starburst.

The same process goes for the third part of the question.

Add the probabilities of the pearlies and the starburst.

4/9 + 2/9 = 6/9 or 2/3.

There is a 2/3 of NOT pulling out a shooter.

Answer 3

1. Add all of them (one bag) then make fractions.

4/9 pearlies
2/9 starburst
3/9 solid shooters

2. Add all the marbles that are not starburst.

7/9 chance

3. Same as above.

6/9

Answer 4

1/9, 7/9, 2/3

Answer 5

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