the area of a rectangle is 27 sq. ft. the base is 3 times more than twice the height. what are the dimensions on the rectangle? what is the area?
i need to show my work too...wouldnt the equation i have to set up be
h x (2h + 3)=27 ??
i tried that but i dont think it worked..
2006-12-04 14:44:30 · 3 answers · asked by rita_the_cheetah 1 in Education & Reference ➔ Homework Help
That is correct.
A = bh = 27
b = 2h + 3
substitute to get your equation
h x (2h + 3) = 27
distribute to get
2h^2 + 3h = 27
2h^2 + 3h - 27 = 0
factor to get
(2h + 9)(h - 3) = 0
h = 3 ft
so b = 9 ft
Check your work
area = 9x3 = 27
b = 9 = 3 x 2(3)
2006-12-04 14:50:38 · answer #1 · answered by emilynghiem 5 · 0⤊ 0⤋
ur quadratic eqn is rite...
jus expand it ...
2h^2 + 3h - 27 = 0...
(2h+9) (h-3) = 0
h = 3 or -9/2...
since the measurement can't be -ve..choose 3...
therefore the h = 3 and the b=9...
2006-12-04 22:56:06 · answer #2 · answered by Anonymous · 0⤊ 0⤋
nm...
i think its 4.5 ... i am not sure though... good luck,...
2006-12-04 22:59:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋