How far will the ball travel before it hits the ground?

Question

A baseball is launched from ground level with initial velocity of 38m/s inclined at 25 degrees to the horizontal.

We established in class that the ball would be in the air for

t = 2v0y /g = 3.3s

Answer 1

.that depends who is swinging at it.
are they on steroids.
does the bat have Cork in it.
how about pine tar,,,
will someone in the crowd interfere and catch it with a glove.
will the person judging it, accept bribes.
the list goes on.

Answer 2

First, you would be able to desire to desire to confirm for the horizontal and vertical factors of the preliminary velocities. So Vh = 8 m/s*cos 60= 4m/s; Vv = 8m/s*Sin 60 = 6.ninety 3 m/s. the project is calling for the horizontal distance so it could desire to be solved by employing utilising the formula Dh = Vh*time (Horizontal distance =Horizontal velocity * complete time of return and forth) Time would desire to desire to be solved by employing utilising utilising the vertical velocity to find the time of ascent then multiply it by employing utilising 2 thinking time of ascent = time of descent. So, t = ((0 m/s -6.ninety 3 m/s) / 9.8m/s2 )*2= a million.40-one s. hence multiplying the horizontal velocity of four m/s with the full time of a million.40-one s will furnish a horizontal distance is 5.sixty 4 m.

Answer 3

let X be the distance
let Y be the height
we have
vx = v * cos 25
vy = v * sin 25 -gt
X = vx * t
Y = -1/2gt^2 * vyt

Xmax = v * cos 25 * tmax = 113.65 m

Answer 4

112.9 m (= 38*cos25*3.3)

Answer 5

wind, humidity, altitude?