A diver of weight 580N stands at the end of a diving board of length L=4.5m and negligible mass.?

Question

The board is fixed to two pedestals separated by distance d=1.5m. Of the forces acting on the board, what are the (a) magnitude and (b) direction (up or down) of the force from the left pedestal and the (c) magnitude and (d) direction (up or down) of the force from the right pedestal? (e) Which pedestal (left or right) is being stretched, and (f) which is being compressed?

Answers :(a) 1.2kN
(b)down
(c)1.7kN
(d)up
(e)left
(f)right

Dont know how they got these answer so if you can please shoe how.

Answer 1

Look at the moments about the right pedestal.

580*(4.5-1.5) = 1.5Fa → Fa = 1160 N down

The force on the right p has to be equal and opposite the sum of the diver's weight and the downward Fa:

Fb = 1160 + 580 = 1740 N up

Answer 2

Torque = rigidity x distance at rt perspective to rigidity T = mg x 4.0 = (100 and twenty)(9.80 one)(4.0) = 4710 N-m CW round pivot end of board i don't understand what "our convention" is? We purely defined torque as: CW or CCW