A bobsled zips down an ice track starting at 150 m vertical distance up the hill. Disregarding friction, what is the velocity of the bobsled at the bottom of the hill? (g=9.81m/s2)
I got 54m/s anyways here are the answer choices:
27m/s
36m/s
45m/s
54m/s
btw i'm asking because for 3 answers in a row i got D so i'm just trying to make sure i'm not messing up here thanks.
2006-12-04 13:38:43 · 4 answers · asked by strawberrylollipop12345 1 in Science & Mathematics ➔ Physics
Yes that's correct.....v = 54.24 m/s
2006-12-04 13:54:03 · answer #1 · answered by Anonymous · 0⤊ 0⤋
you need to know how much the bobsled weighs.
2006-12-04 21:48:59 · answer #2 · answered by Modus Operandi 6 · 0⤊ 0⤋
You don't need the weight if there is no friction.
2006-12-04 21:52:11 · answer #3 · answered by scubamasterme 3 · 0⤊ 0⤋
time = sqrt(2h/g)
time = sqrt(300/9.81) = 5.53 s
velocity = d/t = 150m/5.53s = 27.1 m/s
2006-12-04 21:57:19 · answer #4 · answered by Anonymous · 0⤊ 0⤋