10.50 g of gaseous HCl are dissolved in water to give a final solution of 25.6 mL .
What is the molarity of this solution ?
2006-12-04 13:31:50 · 4 answers · asked by nietzsche 1 in Science & Mathematics ➔ Chemistry
The moler mass of HCL is 36.5(g/mol). so mol of 10.5(g) of gaseous HCL is 10.5/36.5= 0.29 mol. MOLARITY=MOL/VOLUME OF SOLUTION.so 0.29/0.0256(l) gives you 11.2(M).Which is the molarity of this solution.
2006-12-05 00:42:12 · answer #1 · answered by Anonymous · 0⤊ 0⤋
HCl has a molar mass of roughly 36.463 g/mol,
If 10.50 g are in 25.6 mL, there would be 410.16 g per L. 410.16 g is roughly 11.25 moles, so there would be that many moles of HCl in 1 L of water, and the molarity is 11.25.
(That's very strong Hydrochloric acid; I was told a molarity of 6 would be high)
2006-12-04 21:39:43 · answer #2 · answered by dennismeng90 6 · 0⤊ 0⤋
10.50 g of HCl is 10.50/36.5=0.2877 (mol). So the molarity of a final solution of 25.6 mL (or 0.0256 L) is 0.2877/0.0256=11.2 (M)
2006-12-04 21:38:47 · answer #3 · answered by myyahoo! 2 · 0⤊ 0⤋
Molarity has the units of molHCl/1L soln. So you begin with something in the numerator that can become molHCl and something in the denominator that can become 1L soln or 1000mL soln.
10.50gHCl(g)/25.6ml soln x 36.46gHCl(g)/1molHCl(g) x 1000mL soln/1L soln =
the gHCl(g) cancel to give moles HCl. The mLHCl soln cancel to give Lsoln.
2006-12-04 21:39:43 · answer #4 · answered by steve_geo1 7 · 0⤊ 0⤋