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2006-12-04 13:16:01 · 6 answers · asked by a 4 in Science & Mathematics Mathematics

6 answers

A number is divisible by three if the digits, when added together, make a number that is divisible by three. 27= 2+7= 9 which is divisible by three.

If a number is divisible by six, it will be an even number, divisible by three (above). 36= 3+6= 9 which is divisible by three and 36 is an even number so it's divisible by two as well.

A number is divisible by five if it ends in a five or zero, for example, 75 and 130.

A number is divisible by ten if it ends in zero.

A number is divisble by nine if the digits add up to a number divisible by nine. Such as 99 or 108 or 1161.

I hope this helps!

2006-12-04 13:31:24 · answer #1 · answered by Abbey 3 · 0 0

3: Add the digits of the number. The number is divisible by 3 if the sum of the numbers is a multiple of 3.

ex: 141-- 1+4+1=6 which is a multiple of 3.

6: The same as 3, but the number is also even.

5: The number ends in 0 or 5

10: The number ends in 0

9: Add up the digits of the number. It is divisible by 9 if the numbers add up to a multiple of 9.

ex: 288-- 2+8+8=18 which is a multiple of 9.

2006-12-04 21:19:33 · answer #2 · answered by itsacoaster 2 · 0 0

if u add the digits together an that is divisible by 3 then so is your origanal number. if 3 and 2 can go into it so can 6. if it ends in 5 or 0 then 5 can go into it. If it ends in 0 10 can go into it. if the sum of the digits is divisible by 9, so is 9.

2006-12-04 21:27:46 · answer #3 · answered by giRlyGirL 1 · 0 0

3 - the sum of the digits will equal a factor of 3
6 - same as above but will also be an even number
5 - units digit is either 5 or 0
10 - units digit is 0
9 - the sum of the digits will equal a factor of 9

2006-12-04 21:19:47 · answer #4 · answered by Gary H 6 · 0 0

3-if its digits added together = something divisible by 3
6-if its digits added together = something divisible by 6
5 and 10-ends in 0 or 5
9-if its digits added together = something divisible by 6

2006-12-04 21:18:41 · answer #5 · answered by Anonymous · 0 0

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2006-12-04 21:22:08 · answer #6 · answered by araposo185 2 · 0 0

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