I have a 9th grade math (algebra) question for you? Its solving systems of equations?

Question

What is ;; x - 3y= -1 // 2x + 3y=16... you have to use substitution though.... what is the solution?

What is ;; x - 3y= -1 = 2x + 3y=16... you have to use substitution though and find "y" for one of them and "x" for the other.. and if u put them together u will get some coordinates.... what is the solution?

Answer 1

x - 3y = -1.....Eq 1
2x + 3y = 16.....Eq 2
Consider Eq 1
x - 3y = -1
-3y = -1-x
3y = 1 + x
Substitute the value of '3y' in Eq 2
2x + 3y = 16
2x + 1 + x = 16
3x + 1 = 16
3x = 16-1
3x = 15
x = 15/3
x = 5
Substitute the value of 'x' in Eq 1
x - 3y = -1
5 - 3y = -1
-3y = -1-5
-3y = -6
3y = 6
y = 6/3
y = 2
x = 5, y = 2
Coordinates: (5,2)

Answer 2

You can do this one. It's not too hard.

In the first equation, it's very easy to solve for x.

x=3y-1

You now take that x-value that you obtained and put it in where x is, in the second equation.

2(3y-1) + 3y = 16

Simplify

6y - 2 + 3y = 16
9y - 2 = 16

Solve for y

9y=18
y=2

Plug that y-value back in the first equation

x-3(2) = -1
x-6=-1
x=5

So your solution is
x=5, y=2 or (5,2), however your teacher wants you to express your answer.