Please simplify this equation. SHow your work, so we can learn ;)
3a^1 * 4a^3 / 28a^2
2006-12-04 12:36:55 · 7 answers · asked by Digging for answers 3 in Education & Reference ➔ Homework Help
3a^1*4a^3/28a^2
= 12a^(1+3)/28a^2
= 12a^4/28a^2
=3a^(4-2)/7
=3a^2/7
Assuming you know the law of indices
2006-12-04 12:41:48 · answer #1 · answered by the_darkness1900 1 · 2⤊ 0⤋
3a * 4a^3 / 28a^2
= 12a^4 / 28a^2
Simplifiy
= 3a^2/7
That should be the answer
The Simplify is crossing off the numbers by dividing
2006-12-04 12:44:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋
* Divide top and bottom by the greatest common factors:
4, a^2
[4 is greatest common factor of 4, 28]
[a^2 is greatest common factor of a^3 and a^2]
This reduces the fraction to
(3a)*(a) / (7)
this is the same as
3a^2 / 7
* Note: also reduce and combine exponents
so a^1 = a
a*a = a^2
3a^2 / 7 is lowest terms because
* 3 and 7 have no common factors
* There are no other a terms to combine or reduce
2006-12-04 12:42:40 · answer #3 · answered by emilynghiem 5 · 1⤊ 0⤋
3a^1*4a^3/28a^2
= 12a^(1+3)/28a^2
= 12a^4/28a^2
=3a^(4-2)/7
=3a^2/7
It is as easy as that maam
2006-12-04 12:55:15 · answer #4 · answered by Anonymous · 1⤊ 0⤋
check out http://www.schoolpiggyback.com ...you can get other students to answer your question and they're math whizzes...goodluck : )
2006-12-04 12:40:05 · answer #5 · answered by tammy z 1 · 1⤊ 0⤋
PEMDAS!!!!!
2006-12-04 12:44:52 · answer #6 · answered by amazing! 2 · 0⤊ 1⤋
Poop!
2006-12-04 12:38:06 · answer #7 · answered by Anonymous · 0⤊ 2⤋