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Balance these & Idenify what types these are, I'm taking chemistry 1 only
1. CO --» C + O2
2. NaCI + AgNO3 -» NaNO3 + AgCl
3. S + Cl2 -* SCl2
4. BaCI2 + NaOH -» NaCI + Ba(OH)2
5. Zn + CuSO4 -> ZnS04 + Cu
6. CH4 -» C +H2
7. Pb(NO3)2 + Mg ---> Pb + Mg(N03)2
8. Mg + HCl >>> MgCL2 + H2
9. H2S04 ---> H2 + S +O2
lO. O2 + N2 >>> N2O4
11. CaBr2 +Na3P>>> Ca3P2 + NaBr
12. KI + Br2 >>>KBr + I2
13. C6H12O6 >>> C+ H2O
14. NaF >>Na + F2
15. Si + 02 ----> SiO2
16. Nal + Pb(NO3)2 >>>NaNO3 + PbI2
17. Nal + Cs >>> CsI + Na
18. H2 + CO + O2 >>>>H2CO3
19. Li3 PO4 >> Li + P + O2
20. CS2 + F2 >>> CF4 + S
Just Balance these out only::
21. Zn + O2>>ZnO
22. HI>>H2 I2
23. B + F2 >>> BF3
24. N2 + H2 >>NH3
25. Fe + H2O >>> Fe3O4 + H2

2006-12-04 11:27:12 · 5 answers · asked by truckin_90 2 in Science & Mathematics Chemistry

5 answers

For 1-3
1.2CO-2C+O2 decompostion reaction
2. no need balance Double displacement reaction
3. no need balance synthesis reaction

For 21-23
21. 2 Zn+O2-2 ZnO
22. 2HI-H2+ I2
23. 2 B+ 3F2--2BF3

2006-12-04 12:28:16 · answer #1 · answered by shawn s 2 · 0 0

the balanced equation is: Al(NO3)3(aq)+ 3 NaOH(aq)= 3 NaNO3 +AL(OH)3. You were proper about putting the + and - jointly to style the products even if seeing that Al is +3 and OH is -a million you want 3 OH to stability it out. then you definately are making a 'procuring list' and make effective even if that you've on one area equals what you've on the different area for all aspects (Al, N, O, and Na). For this you desire a three on NaOH and a three on NaNO3.

2016-11-23 16:58:53 · answer #2 · answered by hellyer 4 · 0 0

I'll be rude and say that you need to do your own homework. All of these equations are really quite easy to balance. Put coefficients in front of things to make sure that you have the same number of each kind of atom on both sides of the arrow.

2006-12-04 11:32:19 · answer #3 · answered by hcbiochem 7 · 1 0

It sucks that I don't have enough points to vote yet, because you are cheating and I would have voted for the previous person who pointed it out.

2006-12-04 11:43:24 · answer #4 · answered by Mr. Nozalott 2 · 0 0

hey...i've said it before to others but check out http://www.schoolpiggyback.com ....its other smart students that answer questions.....goodluck : ) ....also..if you got some free time and wanna answer questions you can make money doing it...neways...hope it help

2006-12-04 11:40:02 · answer #5 · answered by tammy z 1 · 0 0

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