I assume that you meant to type an x instead of s. In this case, the question is
x^2 = 20x - 100
This is a quadratic (has a x^2 term and an x term), so you have to move everything to the left hand side.
x^2 - 20x + 100 = 0
This factors into
(x - 10)^2 = 0
Taking the square root of both sides, we'd normally add "plus or minus" to the right hand side, but plus or minus 0 is the exact same thing.
x - 10 = 0
x = 10
2006-12-04 10:18:33
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answer #1
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answered by Puggy 7
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First make it = 0
x^2 - 20x + 100 = 0
Then factor by FOIL: (x-10)(x-10) = 0
Then see what value of x makes each expression in the parentheses become 0. Those are your answers (here it's the same answer for both)
2006-12-04 10:14:59
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answer #2
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answered by hayharbr 7
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I believe its
x^2 = 20x-100
x^2 - 20x+100=0
x^2-10x-10x+100=0
(x-10)(x-10)=0
x=10,10
2006-12-04 10:14:42
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answer #3
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answered by Dupinder jeet kaur k 2
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x= square root of 20s-100
s=(x^2+100)/20
you get this from:
x^2 +100 = 20s
2006-12-04 10:14:08
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answer #4
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answered by Anonymous
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Given - x^2 = 20s -100
Factor both sides - x*x=20(s-5)
x= sqrt(20(s-5))
x= sqrt(4)*sqrt(5(s-5)) (Remember that sqrt(ab)=sqrt(a)*sqrt(b))
x= 2*sqrt(5(s-5)
5(s-5) has no more perfect squares that it can factor out (Remember that sqrt(a-b) does NOT equal sqrt(a)-sqrt(b)), so 2sqrt(5*(s-5)) is as far as it goes.
2006-12-04 10:19:00
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answer #5
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answered by dennismeng90 6
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