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2006-12-04 10:11:14 · 5 answers · asked by Detroit Needs Help 2 in Science & Mathematics Mathematics

5 answers

I assume that you meant to type an x instead of s. In this case, the question is

x^2 = 20x - 100

This is a quadratic (has a x^2 term and an x term), so you have to move everything to the left hand side.

x^2 - 20x + 100 = 0

This factors into

(x - 10)^2 = 0

Taking the square root of both sides, we'd normally add "plus or minus" to the right hand side, but plus or minus 0 is the exact same thing.

x - 10 = 0
x = 10

2006-12-04 10:18:33 · answer #1 · answered by Puggy 7 · 2 0

First make it = 0

x^2 - 20x + 100 = 0

Then factor by FOIL: (x-10)(x-10) = 0

Then see what value of x makes each expression in the parentheses become 0. Those are your answers (here it's the same answer for both)

2006-12-04 10:14:59 · answer #2 · answered by hayharbr 7 · 0 0

I believe its
x^2 = 20x-100
x^2 - 20x+100=0
x^2-10x-10x+100=0
(x-10)(x-10)=0
x=10,10

2006-12-04 10:14:42 · answer #3 · answered by Dupinder jeet kaur k 2 · 0 0

x= square root of 20s-100

s=(x^2+100)/20
you get this from:
x^2 +100 = 20s

2006-12-04 10:14:08 · answer #4 · answered by Anonymous · 0 0

Given - x^2 = 20s -100

Factor both sides - x*x=20(s-5)

x= sqrt(20(s-5))
x= sqrt(4)*sqrt(5(s-5)) (Remember that sqrt(ab)=sqrt(a)*sqrt(b))
x= 2*sqrt(5(s-5)

5(s-5) has no more perfect squares that it can factor out (Remember that sqrt(a-b) does NOT equal sqrt(a)-sqrt(b)), so 2sqrt(5*(s-5)) is as far as it goes.

2006-12-04 10:19:00 · answer #5 · answered by dennismeng90 6 · 0 0

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