is this correct?

Question

Write an equation for the reaction of H+ with a solution containing both HCO3- and CO3 2-

(HCO3)- --> (CO3)2- +H+

Answer 1

Sorry, but that is not correct.

Lets avoid equilibrium equations...simply put:

Acid reacts with carbonate ions to form bicarbonate ions:
CO3(-2) + H(+1) ==> HCO3(-1)

If you may add only one H(+1), reaction stops there leaving only HCO3(-1) ions in soln...eg if you started wih Na2CO3, and dried this resultant soln, you would have 2 NaHCO3.
but...

Acid reacts with bicarbonate to liberate CO2
HCO3(-1) +H(+1) ==> CO2(g) + H2O

So, if you may add enough acid to complete the reactions, and if both were present in equimolar amounts, overall equation is:
HCO3(-1) + CO3(-2) +3H(+1) ==> 2CO3(g) + 2H2O

Answer 2

I think it wants H+ as a reactant, not a product. So maybe the reaction should be H+ + (CO3)2- <----> HCO3-

Answer 3

this is an acid dissociation equation involving a weak acid. the reaction can go both ways. you can either change the direction of the arrow, or use a double-sided arrow to show reversibility. all 3 answers are correct.