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at McDonalds you can order chickennuggets in boxes of 6,9 and 20. what is the largest number such that you cannot order any combination for the above to acheive exactly the number you want?
in other words:
if you could buy nuggets in boxes of 6,9,and 20, what is the highest,largest, number that you canno't get from any combination of the boxes of nuggets(box of 6,9,and 20) plz answer ONLY if you know. IF YOU DON"T KNOW DON"T ANSWER!PLZ!

2006-12-04 09:42:32 · 4 answers · asked by the genius 1 in Science & Mathematics Mathematics

tellme a way or strategie you used to get the answer plz!

2006-12-04 09:53:08 · update #1

i just want to know if there is a combo for 1000001?

2006-12-04 10:04:37 · update #2

4 answers

It's an infinite number.

2006-12-04 09:58:24 · answer #1 · answered by Anonymous · 0 2

The answer is 43. Firstly, its easy to check that we can't make up 43.
Now,
44 = 20+6+6+6
45 = 9+9+9+9+9
46 = 20+20+6
47 = 20+9+9+9
48 = 6+6+6+6+6+6+6+6
49 = 20+20+9.
Then you can make up any higher number by adding enough 6s to one of those.

Edit - responding to your next question..
Theres not much you can do in this case other than a bit of trial and error. Just remember that all you need to do is find 6 in a row that you can make, and then you know that you can get everything else after that.

I guess you could apply some maths:
We can use 6 and 9 to get every multiple of 3 from 6 onwards (we have 6 and 9, then add 6s). For numbers that are 1 more than a multiple of 3, we can form them as 20+20 + multiple of three formed previously, as long as those numbers are >= 46. For numbers that are 2 more than a multiple of 3, we can form that as 20 + multiple of three formed previously, as long as those numbers are >= 26.

So we already know we can make everything from 46 onwards; now you can just check backwards a bit and you'll end up at the right answer.

An interesting side point: if you only had 2 combinations, a and b, where a and b didn't share any factors, there *is* a formula: the highest one you can't make is a*b-a-b.

And finally, your last answer.. yes, as I mentioned above, you can get everything from 44 up.
1000001 = 47 + (166659 sixes)
= (20+9+9+9) + (166659 sixes).

2006-12-04 09:46:21 · answer #2 · answered by stephen m 4 · 2 1

It seems to me that a piece of the puzzle is out. I can think right away in 22 that is not achievable by any combination.

21 is (6 + 6 + 9) and then the next one is 24 (6 + 9 +9) . Between 21 and 24 are no combinations possible.

Is a piece left out or a condition you forgot to transcribe?

2006-12-04 09:55:05 · answer #3 · answered by Hector G 1 · 0 2

above answer is right.

you can't make 43 because the lowest thing with '3' at the end you can make from 6 and 9 is 33.

2006-12-04 09:51:41 · answer #4 · answered by Anonymous · 0 2

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