Find three ordered pairs that are solutions of the equation - 4x + 3y =6.?

Answer 1

You should rewrite the equation in linear form...

y = (6 + 4x)/3

Now, when x = 1, 2, 3, y is found to be:

y = (6+4(1))/3 = 3.333

y = (6+4(2))/3 = 4.667

y = (6+4(3))/3 = 6

Thus, three ordered pairs for the equations are:

(1, 3.333)
(2, 4.667)
(3, 6)

Hope that helps! :)

Answer 2

Since this equation has infinitely many solutions, we shouldn't have too much of a problem:
How about the ordered pair that looks like (0,y)? To find y, we substitute 0 for x and solve: -4*0 + 3y = 6, so 3y = 6, thus y = 2.
Hence one ordered pair is (0,2)
Similarly, we can try to find one that looks like (1,y). To find y, we substitute 1 for x and solve: -4*1 + 3y = 6, so -4 + 3y = 6, 3y = 10, thus y=10/3.
Hence another ordered pair is (1, 10/3).
Just make up a value for 'x' and see what 'y' turns out to be!

Answer 3

For x = -2; y = -4(-2) + 3y = 6 => 3y = 6 - 8 => y = -2/3 ----> (x, y) = (-2, -2/3)
For x = -1; y = -4(-1) + 3y = 6 => 3y = 6 - 4 => y = 2/3 ----> (x, y) = (-1, 2/3)
For x = 0; y = -4(0) + 3y = 6 => 3y = 6 => y = 2 ----> (x, y) = (0, 2)
:)*
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Answer 4

x=1 means -4+3y=6
3y=10
y=10/3 ans:x=1,y=10/3
y=1 means -4x+3=6
x=-3/4 ans x=3/4,y=1

Answer 5

- 4x + 3y =6
3y=4x+6
y=4x/3+2

(x, y)
(0, 2)
(3, 6)
(6, 10)

Answer 6

- 4x + 3y =6
3y=4x+6
y=4x/3+2

(x, y)
(0, 2)
(3, 6)
(6, 10)

Answer 7

- 4x + 3y =6
3y=4x+6
y=4x/3+2

(x, y)
(0, 2)
(3, 6)
(6, 10)

Answer 8

If that's not a minus sign in front of the 4, then put a minus sign in front of my X values below.

0,2
3,6
6,10
9,14
12,18
etc. in linear progression.

Answer 9

(0,2)
(-3/2,0)
(3,6)