The length of the rectangle is x metres; 120 metres of fencing is available. Show that the area of the rectangle is 1/2x(120-x)m2."
Who can help me with this maths problem?
2006-12-04 08:12:06 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
A = l(w)
P = 2l + 2w
120 = 2l + w OR 120 = 2w + l
Case 1:
2w = 120 - l
w = 1/2(120 - l)
A = l (w) = l [(1/2)(120 - l)]
since l = x. A = 1/2x(120 - x) meters^2
Since we don't know w, this is meaningless.
2006-12-04 08:28:29 · answer #1 · answered by mattmedfet 3 · 0⤊ 0⤋
The area of a rectangle is the length times the width, yes?
We know that the length is X -- that was given to us.
Since one of the length-sides is a hedge, the amount of fence left over for the width-sides is 120-X.
There are two width-sides -- both the same -- so the width sides must be (120-X)/2.
Multiplying length (X) times width ((120-X)/2) gives us
(X(102-X))/2 -- which is the same as
(X/2)(120-X)
Since the length of the fencing was given, the answer will be in square-meters.
2006-12-04 08:34:34 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Sheep In Pen
2016-12-10 19:57:33 · answer #3 · answered by ? 4 · 0⤊ 0⤋