A student prepares a solution by dissolving 4.84 g of NaCl in enough water to make 200. mL of solu

Question

A student prepares a solution by dissolving 4.84 g of NaCl in enough water to make 200. mL of solution.
The student then transfers 26.0 mL of this solution into a 100. mL volumetric flask. Water is then added
up to the 100. mL mark.
What is the final molarity of NaCl in the 100. mL flask ?

Answer 1

Find the moles of NaCl
4.84/58.5 = 0.0827 moles NaCl

so student takes 26/200 of these moles
which means he took 0.0108 moles of NaCl

so new Molarity = 0.0108/0.100 = 0.108 M

Answer 2

4.84 g /mol.wt of NaCl = No. of moles of NaCl
No.of moles of NaCl/0.2 liter of water = molarity of your solution
26 x molarity of your solution = 100 x molrity of the diluted solution ( which you asked about)
you have to do the calculation , good luck