2006-12-04 05:26:09 · 5 answers · asked by Kpeezy 1 in Science & Mathematics ➔ Chemistry
This is a question from the NY Regents exam
molar mass of He is 1mole=4 g
1 mole anything = 6.022*10^23 particles.
10g He =2.5 moles
so # of He atoms = 2.5*6.022*10^23
2006-12-04 05:30:46 · answer #1 · answered by Math-Chem-Physics Teacher 3 · 0⤊ 0⤋
The atomic weight of He is 4 g/mol. So 10g of He is 10/4=2.5 moles, which is 2.5x6.02x10^23=1.505x10^24 (atoms)
2006-12-04 05:31:11 · answer #2 · answered by myyahoo! 2 · 0⤊ 0⤋
10g/by rmm will give no of mole (5moles)
10/4 = 2.5 moles
no. of moles x avogadros number = no. of atoms
2.5 X 6.022Ã10^23=1.32X10^24atos
2006-12-04 05:29:32 · answer #3 · answered by Jan Zam 1 · 0⤊ 0⤋
just use the period table fella
and know that there are 6.02X10^23 atoms/mol
that should do ya to find the answer on your own
2006-12-04 05:29:14 · answer #4 · answered by hayden160 3 · 0⤊ 0⤋
The guy above me is more correct, I got the same answer as he did, 1.505 x 10^24
2006-12-04 11:42:32 · answer #5 · answered by huggable 2 · 0⤊ 0⤋