Suppose that a brown-eyed man and abrown-eyed woman had blue-eyed child. What is the genotype of the parents?

Answer 1

Let B stand for brown-eyed
and b stand for blue-eyed

the parents both have Bb as their genotype.

you can solve this by using a punnett square. the result will be:

BB-homozygous brown-eyed
Bb-heterozygous brown-eyed
Bb-heterozygous brown-eyed
bb-homozygous blue-eyed

so bb is the blue-eyed child this resulted from the Bb or homozygous brown-eyed parents

Answer 2

1) Let "B" the dominant gen for brown color of eyes and "u" the recessive gen for blue color of eyes.

2) In order that these couple of brown-eyed people have a blue-eyed child the genotype should be:

Woman: Bu
Man: Bu

So, Bu x Bu = BB, Bu, Bu, uu

The last one is the genotype corresponding to blue-eyed child.

Hope it helps!

Good luck!

Answer 3

BROWN-blue and BROWN-blue

Upper case indicating the dominate trait.

Answer 4

They both have a recessive blue. The child got both recessive blues.

Answer 5

brown of blueeye children i think its actually test out there where you can choose the genetic material of your kids