2006-12-04 04:26:21 · 11 answers · asked by Leticia H 1 in Science & Mathematics ➔ Mathematics
x^2 = 49
so x = +/- 7
2006-12-04 04:28:07 · answer #1 · answered by Mein Hoon Na 7 · 1⤊ 0⤋
There are two ways you can do this:
1) Factor and solve.
As you already know, easy quadratics usually involve factoring, and then you equate it to 0 and solve from there. This is no different.
x^2 - 49 = 0
(x - 7) (x + 7) = 0
x = 7, -7
2) Recognize what to do in a situation where you only have x^2 on the left hand side.
If x^2 - 49 =0
then x^2 = 49
From this point, is it ABSOLUTELY imperative that you recognize when taking the square root of both sides of an equation, you have to add "plus or minus" on the right hand side. So, taking the square root of x^2 is just x, while you just take the square root of the right hand side BUT you add a plus or minus.
x = +/- 7
Therefore, x = 7, -7
2006-12-04 05:20:03 · answer #2 · answered by Puggy 7 · 0⤊ 0⤋
x^2 - 49 = 0 (Add 49 to both sides)
x^2 = 49 (Take square root from both sides)
x = +7 or -7
QED
2006-12-04 04:54:41 · answer #3 · answered by CSUFGrad2006 5 · 0⤊ 0⤋
x^2-49=0
move the 49 over to the othe side so you must change the sign
x^2=49
take the square root of both sides
x= root 49
x= + or -7
hope this helps!
2006-12-04 04:37:31 · answer #4 · answered by Just me 5 · 0⤊ 0⤋
7 and -7
2006-12-04 04:28:46 · answer #5 · answered by Betanzos 1 · 1⤊ 0⤋
7 or -7
2006-12-04 04:29:51 · answer #6 · answered by NeverStopQuestioning 2 · 1⤊ 0⤋
x^2 = 49.
so x = 7 or -7
Hope this helps=)
(its pretty easy.)
2006-12-04 04:30:43 · answer #7 · answered by luv_phy 3 · 1⤊ 0⤋
x=+/-7
2006-12-04 04:43:23 · answer #8 · answered by raj 7 · 0⤊ 0⤋
x^2-49=0
x^2=49
x = +-square root of 49
x = 7 or -7
hope this helps
2006-12-04 04:36:38 · answer #9 · answered by whawkeyes06 2 · 1⤊ 0⤋
hi,
x^2 - 49 = 0
x^2 = 49
taking sqrt on both sides,
x = +7 or -7 // taking sqrt for +ve no is either +ve or -ve.
2006-12-04 04:31:44 · answer #10 · answered by candy 2 · 1⤊ 0⤋