I want to know if 1 team has 8 wins and 5 losses and another team has 6 wins, 4 losses, and 3 ties, who is in 1st and who is in 2nd place?
2006-12-04 03:54:28 · 4 answers · asked by Anonymous in Sports ➔ Other - Sports
The 8 win 5 loss team would be in first based on a win percentage of .0615. Even if you discount the 3 ties, the 6 win 4 loss team would be in second based on a win percentage of .600
2006-12-04 03:57:48 · answer #1 · answered by DJ 5 · 0⤊ 0⤋
The 8-5 team is in first place since they have a winning percentage of .615 while the 6-4-3 team has a winning percentage of .461.
2006-12-04 11:58:25 · answer #2 · answered by thewirelessguy999 3 · 0⤊ 0⤋
generally, you either go by win percentage or points:
by win percentage, the first team is at 8/13 = 0.615,
and team 2 is at 6/10 (the ties don't figure in) = 0.6, so team 1 would win
By points (2 for win, 1 for tie), team 1 has 16, and team 2 has 15, so team 1 would win again.
2006-12-04 11:57:39 · answer #3 · answered by TankAnswer 4 · 0⤊ 0⤋
NHL type scoring allows 2 points for a win and 1 point for a tie.
In your example above, the scores are 16 and 15 points respectively.
Murph
2006-12-04 11:59:21 · answer #4 · answered by Murph 3 · 0⤊ 0⤋