I've just stumbled past a Wonderlic test question. This one:
In printing an article of 48,000 words, a printer decides to use two sizes of type. Using the larger type, a printed page contains 1,800 words. Using smaller type, a page contains 2,400 words. The article is allotted 21 full pages in a magazine. How many pages must be in smaller type?
The official answer is 17. Can somebody explain me why that is? How come? If he's got 21 pages, he can fill 20 with the larger type and still has an empty page. Ideas, anyone?
2006-12-04 03:41:06 · 5 answers · asked by Bense 5 in Sports ➔ Football (American)
I'm not a native speaker so I've maybe overread something. But given he has to fill the pages, 17x1800 is 30600. Rest of 17400. Now, I would need to print 4 pages and the font size would need to be far beyond any given value...
2006-12-04 03:48:09 · update #1
48,000 words divided by 1800 large words/page = 26.67 pages, not 20.
L=large type pages
S=small type pages
1800L+2400S=48000
L+S=21
Solving for S gives 17 small-type pages.
2006-12-04 03:48:31 · answer #1 · answered by mungerfish 1 · 1⤊ 2⤋
Bense - You've just got your numbers mixed up in the equation you did. Instead of multiplying the 17 pages by 1,800, you should be multiplying it by 2,400, since you're talking about the small-type pages.
It's easy once you plug in the numbers:
17 small pages at 2,400 words each = 40,800
4 large pages at 1,800 words each = 7,200
Total =48,000
2006-12-04 12:02:33 · answer #2 · answered by Craig S 7 · 0⤊ 0⤋
If you use 17 smaller type pages, you calculate 17*2400.
You will use 4 larger type pages, you calculate 4*1800.
17*2400 = 40,800 words
4*1800 = 7,200 words
40,800 + 7,200 = 48,000 words & 21 pages exactly.
2006-12-04 13:27:03 · answer #3 · answered by ttjakt 6 · 0⤊ 0⤋
has to fill the 21 full pages.
2006-12-04 11:43:48 · answer #4 · answered by David B 6 · 0⤊ 1⤋
You are over-analyzing. They just want to test your math skill.
2006-12-04 11:44:11 · answer #5 · answered by Jet 6 · 0⤊ 1⤋