A circular fountain is surrounded by a circular walkway 42 inches wide. The diameter of the fountain is 18 foot and the water is 3.5 feet deep. What is the area of the walkway?
2006-12-04 03:26:33 · 3 answers · asked by ourdoorsangler 1 in Science & Mathematics ➔ Mathematics
The area of the fountain = pi(18ft)^2
The area of the fountain + walkway = pi(18ft + 42in x 1ft/12in)^2
= pi(18+7/2)^2 = pi[(36 + 7)/2]^2 = pi[(43/2)^2]
The area of the walkway = area of fountain + walkway - area of fountain
2006-12-04 03:33:24 · answer #1 · answered by kellenraid 6 · 0⤊ 0⤋
Find the area of the walkway with the fountain in the center, then subtract out the area of the Fountain.
IE:
area of the whole place:
16 ft. +42 In. +42 in (Both Sides)= 300 in = area of 25ft Diameter circle.
subtract out the area of the fountain (18 ft. Diameter circle).
that will give you the area of the sidewalk.
2006-12-04 03:34:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋
the walkway goes from the edge of the fountain for and addional 42 inches. So the area is the area of the circle made by the outside edge minus the area of the fountain.
A=pi*r^2
2006-12-04 03:32:20 · answer #3 · answered by cheme54b 2 · 0⤊ 0⤋