math question?

Question

there are 3 parts of this question and they are separate answers

a) find slope of line that passes through (3, -4) (-7) (-4)

b) find slope and the y-intercept of line with given equation and sketch andgraph using slope of y-intercept
1.5x-2.4y=3.0

c) find x intercept and y intercept of line with given equation sketch line using the intercepts x-5y=5

Answer 1

1.slope=0

2.2.4y=-0.5x+3.0
multiplying by 10
24y=-50x+30
dividing by 24
y=-50/24+30/24
slope=-25/12
y intercept=(0,5/4)
setting y=0 x intercept (3/5,0)
use the points to graph


3.x-5y=5
setting x=0,y intercept (0,-1)
setting y=0 x intercept (5,0)
use these two points to graph

Answer 2

a) Slope is "rise over run," where rise is change in y and run is change in x. The change in y is -4 - (-4) = 0 and the change in x is -7 - 3 = -10, so the slope is 0 / -10 = 0. Slope is 0 because this is a horizontal line (with no change in y).

b) You should convert this into slope-intercept form. Use algebra to get the y term alone on one side of the equation, then divide both sides by the coefficient of y to get y = mx + b, where m is the slope and b is the y-intercept. Remember that the y-intercept is the value of y where the line intersects the y-axis.

c) You can find the intercepts by using a value of zero for each variable in turn. Set x = 0 and solve for y, giving you the y-intercept. Then set y = 0 and solve for x, giving you the x -intercept. The intercepts are the values where the line intersects each axis.

Answer 3

a) Horizontal line. Slope = 0

b) 2.4y = 1.5x - 3 multiple by 2.4

y = 3.6x - 7.2

slope = 3.6

y-int = 0.5


c) when x = 0 y = -1 (x-int)

when y = 0 x =5 (y-int)

Answer 4

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