Dan can clean the garage in 6 hours. Bea can do the same job in 8 hours. If they work together, how long will it take them to clean the garage?
2006-12-04 00:23:58 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
I get the same as "Mr.Bill".
Another way to work it out is: 2 Dans could do it in 3 hours,
2 Beas could do it in 4 hours.
so, 1 Dan + 1 Bea can do it in half of each.
i.e. 1 Dan (1&1/2 hours) + 1 Bea (2 hours) = 3 &1/2 hours.
2006-12-04 01:11:37 · answer #1 · answered by cloud43 5 · 0⤊ 0⤋
Let's say each one cleans the garage alone. The average time they need is 7 hours (8 + 6 = 14 / 2 = 7).
Now, if they clean it together, they will only need half the time one of them would need to do it alone, hence 7 / 3 = 3.5 hours.
2006-12-04 00:33:51 · answer #2 · answered by MrBill 2 · 0⤊ 0⤋
8+6=14 total hours for finished job separately
14 (hours) divided by 2 (people)= 7 hours
can be done in 7 hours with both people working
2006-12-04 00:36:03 · answer #3 · answered by Anonymous · 0⤊ 0⤋
8 + 6 = 14
14 man hours in total
divide by 2
7 hours is the answer if one person was to do the job. Since there are two of them, 3.5 hours.
2006-12-04 00:31:36 · answer #4 · answered by Anonymous · 0⤊ 0⤋
this is the right answer here?
you put 1/6x+1/8x=
48(1/6x+1/8x)=48
8x+6x=48
x=48/14
x=24/7
2006-12-04 00:42:31 · answer #5 · answered by Jason 4 · 0⤊ 0⤋
Dony noew ...I was too busy doing my own homework , i didnt have time to do yours as well........diiick wad
2006-12-04 00:46:46 · answer #6 · answered by Anonymous · 0⤊ 0⤋