2006-12-03 23:47:59 · 7 answers · asked by Thomas and M 1 in Science & Mathematics ➔ Mathematics
this is a straight line.Hence its equation is y=mx+c.Where m is the slope of the line.Rearanging this we have
y=(-3/4)x+(5/4).Comparing with the above equation we have
m=(-3/4)
NOTE:-
usually m=(- (coefficient of x)/(coefficient of y))
2006-12-03 23:56:25 · answer #1 · answered by sudhan 2 · 1⤊ 0⤋
4y = -3x+5
>> [4y = -3x+5] 1/4
>> y = -3/4x+5/4
>>m= -3/4 b= 5/4
>> slope is -3/4
2006-12-04 09:01:30 · answer #2 · answered by Sapph 3 · 0⤊ 0⤋
4y + 3x = 5 ==> 4y = -3x + 5
==> y = -3x/4 + 5/4
Hence, the slope of 4y + 3x = 5 is -3/4.
2006-12-04 07:54:18 · answer #3 · answered by Sheila 2 · 0⤊ 0⤋
U r dumb. Nyways here's the solution.
4y=-3x + 5
y=(-3/4)x + 5/4
This is of the form y = mx+c, where 'm' is the slope of the line.
m=-3/4
2006-12-04 09:46:09 · answer #4 · answered by raghunandan r 1 · 0⤊ 0⤋
y=mx+c
slope =m
therefore slope =-3/4
2006-12-04 07:54:58 · answer #5 · answered by lovegirl_hk 2 · 0⤊ 0⤋
4y = -3x+5
Y = -3/4 x +5
Slope is -0.75 or -3/4
2006-12-04 07:52:42 · answer #6 · answered by maussy 7 · 0⤊ 0⤋
slope=-(coeff of x)/coeff of y
=-3/4
2006-12-04 07:55:03 · answer #7 · answered by Dupinder jeet kaur k 2 · 0⤊ 0⤋