calculus help please!!!! thank you very much!!!?

Question

find the acute angle between the curves
1. x^2 + y^2=5 and y^2=4x + 8

Answer 1

Step 1. Find the intersection (x,y)
Step 2a Find the derivative function of x^2 + y^2=5
Step 2b Find the dy/dx of x^2 + y^2=5 in the intersection
Step 2c Find the angle whose tan equals 2b
Step 3a Find the derivative function of y^2=4x + 8
Step 3b Find the dy/dx of y^2=4x + 8 in the intersection
Step 3c Find the angle whose tan equals 3b
Step 4 Calculate |the difference of the angles 2c and 3c|
Good luck Gen

Th

Answer 2

substituting y^2=4x + 8 in the other

x^2+4x + 8=5
x^2+4x+3=0
now find two numbers suc that their product is three and their sum is 4. 3 isprime so its easy, the numbrs is 1 and 3.
see 1*3 = 3 and 1*4 = 4
spliting 4x into that numbers]

X^2 + x + 3x+3 =0
(x^2+x) + (3X+3) = 0

[x(x+1)+3(x+1)] = 0

(x+1) (x+3) =0

if two numbers on multiplying gives zero then either or both of themmust be zero...

so
x+1 must be zore

or
x+3 =o

if x+1 = 0 , then x= -1 and if x+3 = 0 then x= -3....


if x = -1,
y^2 = -4+8=4

y = +2, -2,.

if x= -3

y^2 = -12+8 = -4

if u have studied Complex numbers then y = +2i,-2i;

or simply solution does not exists in real numbers....

so answrs
x = -1, y = 2, -2
x = -3 , y = 2i, -2i, or solution does not exists inreal numbers...

Answer 3

x=-3,x=-1 and y=-4,y=4

Answer 4

i dont now alot about calculus because i finished school at a 11 so i dont now to you now any english people i am a traveller girl you get throw this cam down you do it i dont even now what 1x^2+y^2=5and y^2=4x+8 sorry i wish i could help sorry

Answer 5

find the point of intersection
(-1,-2) and (-1,2)
and angle between the tangents through these points

Answer 6

Sorry I haven't reached that level of Math yet, maybe you could try the following website if you can't get your answers here.

Answer 7

Do your own homework.