I have a Reynolds pen, which can not only solve any algebric or calculus problems, but also draw pictures, write stories in any language on earth, write poems, and so on....
2006-12-03 21:24:36
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answer #1
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answered by ravish2006 6
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First step -- isolate between the variables. hence, upload 3/y to each area of the decrease equation. This leaves you with that equation examining a million/x = 3/2 + 3/y. Invert each area, leaving x = a million/(3/2 + 3/y). Plug this fee for x into the proper equation, which then will change into 4/(a million/(3/2 + 3/y)) + a million/y = 5/3. yet a million/(a million/(3/2 + 3/y)) = 3/2 + 3/y, so multiplying this with the aid of four provides 12/2 + 12/y + a million/y = 5/3. putting each of the y's on one area and each of the numbers on the different provides 12/y + a million/y = 5/3 - 12/2. including those provides 13/y = (-6+5/3) = -18/3 + 5/3 = -13/3. for this reason y = -3. Plugging this fee for y into the proper equation yields 4/x + a million/(-3) = 5/3 including a million/3 to both area yields 4/x = 5/3 + a million/3 . or 6/3, or 2. seeing that 4/x = 2, x ought to equivalent 2. Checking, utilising both values, 4/2 + a million/(-3) = 5/3, and a pair of - a million/3 = 5/3 a million/2 -(3/-3) = 3/2, and a million/2 + a million = 2.
2016-11-23 15:48:21
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answer #2
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answered by Anonymous
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UseYourBrain Company
2006-12-03 21:23:22
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answer #3
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answered by Anonymous
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If one existed, it would simply have a calculator in the side. Even if it were mechanized to write by itself, the font would be a dead giveaway, if you were trying to cheat on a test. The professor would think you typed the answers somehow.
2006-12-03 21:27:16
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answer #4
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answered by CaliCali 2
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Oh please..........comon now.
2006-12-03 21:25:05
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answer #5
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answered by Tosh 3
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PARKER
2006-12-03 21:22:11
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answer #6
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answered by curious 1 1
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