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A block of wood floats in fresh water with two-thirds of its volume V submerged and in oil with 0.90V submerged. please explain how to find the density of the wood and oil, thanks!

2006-12-03 19:42:14 · 2 answers · asked by uoprummel 2 in Science & Mathematics Physics

2 answers

Let density of wood=dw; density of oil=do; desity of water=1g/cc
2/3*V=weight of water displaced=weight of wood=V*dw; hence
dw=2/3 g/cc.
0.9*V*do=weight of wood=V*dw=V*2/3; hence do=0.74 g/cc

2006-12-03 20:06:31 · answer #1 · answered by Mesab123 6 · 2 1

mesab gave that i think.

2006-12-03 20:12:22 · answer #2 · answered by Naddi S 1 · 0 1

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