sum of all terms of decreasing G.P is 16/3 progression contains a term equal to 1/6. ratio of sum of all ter?

Question

sum of all terms of decreasing G.P is 16/3 progression contains a term equal to 1/6. ratio of sum of all terms preceding these term to the sum of these following this term is 30 . Determine the no of term equal to 1/6.

Answer 1

Sn=16/3
Sn=a*(r^n-1)/(r-1)
tk=1/6
tk=ar^(k-1)
[a(r^k-1)(/k-1)]/{ar^(n-k)-1}/...

Answer 2

Sn=16/3
Sn=a*(r^n-1)/(r-1)
tk=1/6
tk=ar^(k-1)
[a(r^k-1)(/k-1)]/{ar^(n-k)-1}/n-k-1]=30