Ok I have a rock with 4 minerals in it. 35% is A, 10% is B, 15% is C, and 40% is D. All I care about is the Copper bearing minerals which would include C and D. How would I go about normalizing C and D to 100% so that I can work with just them? I know this should be really easy but its late and I have no math book or time to search the web. Help? Thanks very much!
2006-12-03 19:35:22 · 3 answers · asked by FuriousLightning 1 in Science & Mathematics ➔ Mathematics
I'm not sure what you mean by 'normalizing' them. If you mean treating them as if they were the total composition of the rock, then just subtract 45% of the mass of the rock to get the total amount of C and D. Now, since 15% of the original mass is C and 40% was D, they will still be in the ratio of 15/40 and the % of C will be 15/55*100 = 27.27% and the % of D will be
40/55*100 = 72.72%.
Hope that helps.
DOug
2006-12-03 19:48:39 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
Not entirley sure of your question. This is what i'd do though.
Make a 100 gram...mole...whatever you are dealing with...basis
I'll just say grams
So component C is 15 grams and D is 40 grams. Just deal with it like that then you can extrapolate your answer back to the beginning.
Or...
make C & D = 100 grams
15+40 = 55
so you have 15/55 *100 grams of C
and 40/55 *100 grams of D.
I think the second one after thinking about it makes more sense...but i'll leave them both in. I normally go with the first approach..but it depends on waht type of calculations you ahve to do. Both will work.
2006-12-03 19:50:15 · answer #2 · answered by My name is not bruce 7 · 0⤊ 0⤋
If you mean you're interested only in the proportion of C to D, which is 15 to 40, then the percentages (of C or D in the total of C and D) are
100%*15/(15+40) and 100%*40/(15+40).
But if you're interested in the proportions of C to D to the rest, which is 15 to 40 to 45, then the percentages are of course
15%, 40% and 45%.
2006-12-03 20:02:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋