A ball is being released onto a ramp that is on a table that ends where the ramp does. When the ramp stops, the ball will fly into the air into a can.
Using this equation: ∆y = vy i t + ½ gt2 (the gt is raised to the 2 power, not times two), what is the time it would take, t, for a ball to fall from the bottom end of the ramp and land into a can that is 10.5 cm tall
g= -9.81m/s
vx = .63m
the distance from the ramp to the can is 1.75 m
2006-12-03 18:36:25 · 2 answers · asked by susie q 2 in Science & Mathematics ➔ Physics
vyi= 0
legnth of table = 1 meter
2006-12-03 18:59:34 · update #1
You are short a whole lot of information, such as angle of the rammp, length of the ramp, (or vyi), height of the table, etc.
2006-12-03 18:45:43 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
this is the kind of thing that is focused on by government schools, rather than teaching how to have independent thought and creative visualization skills
2006-12-04 02:46:19 · answer #2 · answered by hell oh 4 · 0⤊ 1⤋